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3
4
3
4
0
\dfrac{343}{40}
4
0
3
4
3
3
4
3
4
0
\dfrac{343}{40}
4
0
3
4
3
The largest number that divides
3
4
3
and
4
0
343\text{ and }40
3
4
3
and
4
0
is
1
1
1
, so the GCD =
1
1
1
3
4
3
4
0
\dfrac{343}{40}
4
0
3
4
3
can be reduced, since
1
1
1
is a factor of both
3
4
3
343
3
4
3
and
4
0
40
4
0
:
3
4
3
4
0
÷
1
1
=
3
4
3
4
0
\dfrac{343}{40} \div \dfrac{1}{1} = \dfrac{343}{40}
4
0
3
4
3
÷
1
1
=
4
0
3
4
3
The fraction is now in lowest terms